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- \title[Method of moments for $\PBzero \to \PKstar \mu \mu$]{Method of moments for $\PBzero \to \PKstar \mu \mu$}
- \author{Marcin Chrz\k{a}szcz$^{1,2}$, Nicola Serra$^{1}$}
- \institute{$^1$~University of Zurich,\\ $^2$~Institute of Nuclear Physics, Krakow}
- \date{\today}
-
- \begin{document}
- % --------------------------- SLIDE --------------------------------------------
- \frame[plain]{\titlepage}
- \author{Marcin Chrz\k{a}szcz}
- % ------------------------------------------------------------------------------
- % --------------------------- SLIDE --------------------------------------------
-
- \begin{frame}\frametitle{Quo vadis $\PBzero \to \PKstar \mu \mu$?}
-
- \center \includegraphics[width=0.8\paperwidth]{diagram.png}\\
-
- \end{frame}
- %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
- \begin{frame}\frametitle{Quo vadis $\PBzero \to \PKstar \mu \mu$?}
-
- \center \includegraphics[width=0.8\paperwidth]{diagram_mm.png}\\
-
- \end{frame}
-
-
- \section{Introduction}
- \begin{frame}\frametitle{Introduction}
- Why method of moments:
- \begin{enumerate}
- \item Complementary approach to LL fits.
- \item Allows to extract info measuring quantities in event basis depending on the angular distribution.
- \item Used in $\PB \to \rho \Plepton \nu$(SLAC-386 UC-414),\\ $\PJpsi \to \PK \PK \gamma$(PRD 71, 032005 (2005) ), etc.
- \end{enumerate}
-
-
- \end{frame}
- \section{Method of Moments - Theory}
- \begin{frame}\frametitle{Method of moments}
- {~}
- Let's assume we have our pdf with $k$ unknown parameters:~$PDF(x_i, \alpha)$, $dim(\alpha)=k$. One can calculate $k$ moments, which are the functions of $\alpha_i$:
- \begin{equation}
- \mu_i=f(\alpha_1,..., \alpha_k) = E[W_i]
- \end{equation}
- For $n$ events, we can estimate:
- \begin{equation}
- \widehat{\mu}_i=\dfrac{1}{n}\sum_{j=0}^{j=n-1} w_j
- \end{equation}
- , where $w_j=g(x_i)$
-
- \end{frame}
-
- \begin{frame}\frametitle{Trivial example}
- {~}
- Lets see how this works in practice:
- \begin{equation}
- f(x)=\dfrac{x^{a-1}e^{-x/b}} {b^a \Gamma(a)}
- \end{equation}
- we measure the moments:\\
- \begin{center} $m_1=\dfrac{X_1+X_2+...+X_n}{n}$,\\ $m_2=\dfrac{X_1^2+X_2^2+...+X_n^2}{n}$.\\\end{center}
- and calculate them analytically:
- \begin{center} $m_1=ab$, $m_2=b^2a(a+1)$\end{center}
- So one just needs to solve this and get the answer:
- \center $a=\dfrac{m_1^2}{m_2-m_1^2}$, $b=\dfrac{m_2-m_1^2}{m_1}$
- \end{frame}
-
- \section{Moments of Ss}
-
-
- \begin{frame}\frametitle{Our PDF}
- {~}
- The angular terms:
- \begin{small}
- \begin{multline}
- PDF(\cos \theta_k ,\cos \theta_l, \phi) =\dfrac{9}{32\pi}( \dfrac{3}{4}(1-F_l)\sin^2 \theta_k + F_l \cos^2 \theta_k + (\dfrac{1}{4}(1-F_l)\sin^2 \theta_k \\ -F_l\cos^2) \cos 2\theta_l + S_3 \sin^2 \theta_k \sin^2 \theta_l cos2\phi + S_4 \sin2 \theta_k \sin \theta_l \cos\phi +\\ S_5 \sin 2 \theta_k \sin \theta_l \cos \phi + (S_{6s} \sin^2 \theta_k + S_{6c} \cos^2 \theta_k) \cos \theta_l + \\ S_7 \sin 2\theta_k \sin \theta_l \sin \phi + S_8 \sin 2 \theta_k \sin 2 \theta_l \sin \phi + S_9 \sin^2 \theta_k \sin^2 \theta_l \sin 2 \phi)
- \end{multline}
- \end{small}
- \only<1>{
- Since we are fitting a PDF we need to ensure it is normalized:
- \begin{equation}
- \int_{-\pi}^{\pi} d\phi \int_{-1}^{1} d cos\theta_l \int_{-1}^{1} d cos\theta_k \dfrac{d^4\Gamma}{dq^2 dcos\theta_k dcos\theta_l d\phi}=1
- \end{equation}
- }
- \only<2>
- {
- \begin{small}
- For further use let's introduce a notation:
- \begin{multline}
- PDF(\cos \theta_k ,\cos \theta_l, \phi) =\dfrac{9}{32\pi}( \dfrac{3}{4}(1-F_l)\sin^2 \theta_k + F_l \cos^2 \theta_k + \\(\dfrac{1}{4}(1-F_l)\sin^2 \theta_k -F_l\cos^2) \cos 2\theta_l + \sum_{x=3}^{9} S_x f_x(\cos \theta_k ,\cos \theta_l, \phi)
- \end{multline}
- \end{small}
- }
-
- \end{frame}
-
- \begin{frame}\frametitle{Moments for $\PB \to \PKstar \mu \mu$ 1/2}
- {~}
- \begin{footnotesize}
-
-
-
- Let's calculate the moments(means of the given distribution):
- \begin{equation}
- \int_{-1}^{1}d\cos \theta_l \int_{-1}^{1}d\cos \theta_k \int_{-\pi}^{\pi}d\phi PDF(\cos \theta_k ,\cos \theta_l, \phi) \sin^2 \theta_k =\frac{2}{5} (2-F_l)
- \end{equation}
- \begin{equation}
- \int_{-1}^{1}d\cos \theta_l \int_{-1}^{1}d\cos \theta_k \int_{-\pi}^{\pi}d\phi PDF(\cos \theta_k ,\cos \theta_l, \phi) \cos^2 \theta_k =\frac{1}{5} (2F_l+1)
- \end{equation}
- \begin{equation}
- \int_{-1}^{1}d\cos \theta_l \int_{-1}^{1}d\cos \theta_k \int_{-\pi}^{\pi}d\phi PDF(\cos \theta_k ,\cos \theta_l, \phi) \cos^2 \theta_k \cos 2\theta_l =-\dfrac{2}{25}(2 + F_l)
- \end{equation}
- \begin{equation}
- \int_{-1}^{1}d\cos \theta_l \int_{-1}^{1}d\cos \theta_k \int_{-\pi}^{\pi}d\phi PDF(\cos \theta_k ,\cos \theta_l, \phi) \sin^2 \theta_k \cos 2\theta_l=-\dfrac{1}{25}(1+8F_l)
- \end{equation}
- \end{footnotesize}
-
- \end{frame}
-
-
- \begin{frame}\frametitle{Moments for $\PB \to \PKstar \mu \mu$ 2/2}
- {~}
-
-
- \begin{small}
-
- Let's calculate the moments(means of the given distribution):
- \begin{equation}
- \int_{-1}^{1}d\cos \theta_l \int_{-1}^{1}d\cos \theta_k \int_{-\pi}^{\pi}d\phi PDF(\cos \theta_k ,\cos \theta_l, \phi) f_{S_x}= \frac{8}{25}S_x,
- \end{equation}
- for $x=3,4,8,9$, and:
-
- %%
- \begin{equation}
- \int_{-1}^{1}d\cos \theta_l \int_{-1}^{1}d\cos \theta_k \int_{-\pi}^{\pi}d\phi PDF(\cos \theta_k ,\cos \theta_l, \phi) f_{S_x}= \frac{2}{5}S_x,
- \end{equation}
- for $x=5,6,7$.\\
- New physics apparently as we like orthogonal world:
- \begin{equation}
- \int_{-1}^{1}d\cos \theta_l \int_{-1}^{1}d\cos \theta_k \int_{-\pi}^{\pi}d\phi~( f_{S_x} \times f_{S_y}) = \alpha_{xy} \delta_{x~y}
- \end{equation}
-
- \end{small}
- \end{frame}
-
-
-
- \begin{frame}\frametitle{Moments for $\PB \to \PKstar \mu \mu$}
- {~}
- \begin{itemize}
- \item We are abusing the fact that the basis is orthogonal and moments do not mix.
- \item Makes live easier and reduces the systematics.
- \item Each of the S does not know about other.
- \item In case of full PDF, $S_{1s}$, $S_{2s}$, $S_{1c}$, $S_{2c}$ $S_{6s}$, $S_{6c}$ are not orthogonal.
- \item Still we can get them solving equation system:
- \end{itemize}
- \begin{equation}
- \dfrac{d^3\Gamma}{\Gamma dcos\theta_k dcos\theta_l d\phi} sin^2 \theta_k cos \theta_l = 0.1(S_6c+4S_6s)
- \end{equation}
- \begin{equation}
- \dfrac{d^3\Gamma}{\Gamma dcos\theta_k dcos\theta_l d\phi} cos \theta_l = 0.25(S_{6}c+2S_{6s})
- \end{equation}
-
- \small solution: $S_{6c}=2 (4 M_{S_{6c}} - 5 M_{S_{6s}})$, $S_{6s}= -2 M_{S_{6c}} + 5 M_{S_{6s}}$
-
-
-
- \end{frame}
-
-
-
- \section{Toy MC study}
-
- \begin{frame}\frametitle{Moments for $\PB \to \PKstar \mu \mu$}
- {~}
- Lets see if this method actually works. Let's take some random parameters for the PDF and make a toy.
- \begin{columns}
- \column{2.5in}
- \includegraphics[scale=0.25]{images/J3.png}
-
- \column{2.5in}
- \includegraphics[scale=0.25]{images/J9.png}
-
-
- \end{columns}
-
- \end{frame}
-
-
-
-
-
- \begin{frame}\frametitle{Error Estimation}
- {~}
- \begin{itemize}
- \item Since moment is the mean of a given distribution the error can be estimated as $mean/RMS$
- \item use TOY MC to check this assumption
- \item Do not worry, detail description an numbers will come in other presentation.
- \end{itemize}
-
- \includegraphics[scale=0.3]{plots/conw.png}\\
-
-
- \end{frame}
- %%%%%%%%%%%%%%%%%%%%%%%%5
- \begin{frame}\frametitle{Correlation check}
- {~}
- \begin{itemize}
- \item In theory $S_i$ shouldn't be correlated to $S_j$ in the moment calculation.
- \item Lets put this to a test.
- \end{itemize}
-
- \begin{columns}
- \column{2.5in}
- \includegraphics[scale=0.2]{plots/J9J4.png}\\
-
-
- \column{2.5in}
- \includegraphics[scale=0.2]{plots/J8J5.png}\\
-
-
- \end{columns}
-
-
- \end{frame}
-
-
- %%%%%%%%%%%%%%%%%%%%%%%%5
- \begin{frame}\frametitle{Correlation check 2}
- {~}
- \begin{itemize}
- \item Let's now FIX $J_x$ and simulate different $J_y$
- \item Again theory would suggest that one J shouldn't know about the other, so $J_x$ shouldn't change with scanning $J_y$ parameter
- \end{itemize}
-
- \begin{columns}
- \column{2.5in}
- \includegraphics[scale=0.24]{plots/J5_vs_J9_300.png}\\
-
-
- \column{2.5in}
- \includegraphics[scale=0.24]{plots/J3_vs_J9_300.png}\\
-
-
- \end{columns}
-
-
- \end{frame}
-
-
-
- \section{S-wave}
-
-
-
- \begin{frame}\frametitle{S-wave pollution}
- {~}
- \begin{columns}
- \column{3in}
- \begin{itemize}
- \item Unfortunately in our perfect orthogonal world lives an imposter.
- \item This imposter is $\PBzero \to (\PK \Ppi)_{S-wave}~\mu \mu$
- \item This "ghost" dilutes our NP! Like dark matter the universe.
- \item We need something to bust this ghost away
- \end{itemize}
-
- \column{2in}
- \includegraphics[width=0.95\textwidth]{P5.png}\\
-
- \includegraphics[width=0.5\textwidth]{gb.jpg}
- \end{columns}
-
-
- \end{frame}
-
-
-
-
-
- %%%%%%%%%%%%%%%%%%%5
- \begin{frame}\frametitle{S-wave hunting}
- {~}
- Our PDF with the S-wave will look as follows:
- \begin{multline}
- PDF_{full}(\cos \theta_k ,\cos \theta_l, \phi) =\dfrac{9}{32\pi}( \textcolor{red}{(1-F_s)}(\dfrac{3}{4}(1-F_l)\sin^2 \theta_k + F_l \cos^2 \theta_k + \\ (\dfrac{1}{4}(1-F_l)\sin^2 \theta_k -F_l\cos^2) \cos 2\theta_l + S_3 \sin^2 \theta_k \sin^2 \theta_l cos2\phi + \\S_4 \sin2 \theta_k \sin \theta_l \cos\phi + S_5 \sin 2 \theta_k \sin \theta_l \cos \phi + \\ (S_{6s} \sin^2 \theta_k + S_{6c} \cos^2 \theta_k) \cos \theta_l + S_7 \sin 2\theta_k \sin \theta_l \sin \phi + \\ S_8 \sin 2 \theta_k \sin 2 \theta_l \sin \phi + S_9 \sin^2 \theta_k \sin^2 \theta_l \sin 2 \phi) + \\
- \textcolor{red}{\dfrac{2}{3} F_s \sin^2 \theta_l + \frac{4}{3} A_s \sin^2 \theta_l \cos \theta_k + I_4 \sin \theta_k \sin 2 \theta_l \cos \phi} \\ \textcolor{red}{+ I_5 \sin \theta_k \sin \theta_l \cos \phi + I_7 \sin \theta_k \sin \theta_l + \sin \phi + I_8 \sin \theta_k \sin 2\theta_l \sin\phi})
- \end{multline}
-
- \small In this form we ensure normalization.
- \end{frame}
-
- \begin{frame}\frametitle{How does the dilution work? 1/2}
- {~}
- \begin{small}
- \begin{equation}
- \int_{-1}^{1}d\cos \theta_l \int_{-1}^{1}d\cos \theta_k \int_{-\pi}^{\pi}d\phi PDF_{full}(\cos \theta_k ,\cos \theta_l, \phi) f_{S_x}= \frac{8}{25}S_x\textcolor{red}{(1-F_s)},
- \end{equation}
- for $x=3,4,8,9$, and:
-
- %%
- \begin{equation}
- \int_{-1}^{1}d\cos \theta_l \int_{-1}^{1}d\cos \theta_k \int_{-\pi}^{\pi}d\phi PDF_{full}(\cos \theta_k ,\cos \theta_l, \phi) f_{S_x}= \frac{2}{5}S_x\textcolor{red}{(1-F_s)},
- \end{equation}
- for $x=5,6,7$.\\
- Not much harm and easy to control.
- \end{small}
-
- \end{frame}
-
- \begin{frame}\frametitle{How does the dilution work? 2/2}
- {~}
- \begin{small}
- Unfortunately $F_l$ and $F_s$ will mix with each other:
- \begin{multline}
- \int_{-1}^{1}d\cos \theta_l \int_{-1}^{1}d\cos \theta_k \int_{-\pi}^{\pi}d\phi PDF_{full}(\cos \theta_k ,\cos \theta_l, \phi) \sin^2 \theta_k= \\ \frac{2}{15} (6 + 3 F_l (F_s-1) - F_s)=M_{F_l}
- \end{multline}
- \begin{multline}
- \int_{-1}^{1}d\cos \theta_l \int_{-1}^{1}d\cos \theta_k \int_{-\pi}^{\pi}d\phi PDF_{full}(\cos \theta_k ,\cos \theta_l, \phi) \sin^2 \theta_l= \\ \frac{1}{5} (3 + F_l + F_s - F_l F_s)=M_{F_s}
- \end{multline}
-
- They can solve this system:
-
- $ \begin{cases} F_s = \frac{15}{4} (M_{F_l} + 2 M_{F_s}) \\ F_l = \frac{(15 M_{F_l} + 10 M_{F_s}-18)}{(15 M_{F_l} + 30 M_{F_s}-34)} \end{cases}$
-
-
- \end{small}
-
- \end{frame}
-
-
- \begin{frame}\frametitle{S-wave moments}
- {~}
- We can even measure directly the S-wave:
- \begin{equation}
- \dfrac{d^3\Gamma}{\Gamma dcos\theta_k dcos\theta_l d\phi }sin^2 \theta_l cos \theta_k = \dfrac{32 I_{1b} }{45}
- \end{equation}
- \begin{equation}
- \dfrac{d^3\Gamma}{\Gamma dcos\theta_k dcos\theta_l d\phi } sin \theta_k sin 2 \theta_l cos \phi = \dfrac{16 I_4 }{45}
- \end{equation}
- \begin{equation}
- \dfrac{d^3\Gamma}{\Gamma dcos\theta_k dcos\theta_l d\phi } sin\theta_k sin\theta_l cos\phi = \dfrac{4 I_5 }{9}
- \end{equation}
- \begin{equation}
- \dfrac{d^3\Gamma}{\Gamma dcos\theta_k dcos\theta_l d\phi} sin \theta_k sin 2 \theta_l sin \phi = \dfrac{4 I_7 }{9}
- \end{equation}
- \begin{equation}
- \dfrac{d^3\Gamma}{\Gamma dcos\theta_k dcos\theta_l d\phi} sin \theta_k sin2 \theta_l sin \phi = \dfrac{16 I_8 }{45}
- \end{equation}
-
-
-
- \end{frame}
-
-
- \begin{frame}\frametitle{Conclusions}
- {~}
- \begin{itemize}
- \item Method of moments very suitable for $\PBzero \to \PKstar \mu \mu$.
- \item The method converge fast and works for the "simple case", i.e. signal only.
- \item Method very insensitive to S-wave component, thanks to orthogonality.
- \item Complementary one can measure in-depended S-wave component.
- \item No problem with boundary problems.
-
- \end{itemize}
- What comes in the next talks(stay tuned):
- \begin{itemize}
- \item Sensitivity will be given tmr.
- \item This method reduces the error on unfolding.
- \item Systematics easy accessible.
- \end{itemize}
-
-
- \end{frame}
- %%%%%%%%%%%%%%%%%%%%%%%%%55
- \begin{frame}\frametitle{~}
- {~}
- \center \Huge BACKUPS
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- %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
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- %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
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-
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-
-
- %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
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-
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-
- %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
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-
-
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- \end{frame}
-
-
- %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
- \begin{frame}
- {~}
-
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-
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- {~}
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-
-
- \end{columns}
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-
- %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
- \begin{frame}
- {~}
-
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-
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-
-
- \end{columns}
- \end{frame}
-
- %%%%%%%%%%%%%%%%%%%%%%%
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- {~}
-
- \begin{columns}
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- \end{columns}
-
- \end{frame}
-
-
-
-
- % ------------------------------------------------------------------------------
- \end{document}